p = 1 / (1 + exp(-s)) 1 + exp(-s)= 1/ p exp(-s) = 1/p - 1 -s = log(1/p-1) p = 0.9 s = -log(1/p-1)Test
Donnerstag, 23. März 2017
relation log2 asinh
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p = 1 / (1 + exp(-s)) 1 + exp(-s)= 1/ p exp(-s) = 1/p - 1 -s = log(1/p-1) p = 0.9 s = -log(1/p-1)Test